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0=x^2+9x-323
We move all terms to the left:
0-(x^2+9x-323)=0
We add all the numbers together, and all the variables
-(x^2+9x-323)=0
We get rid of parentheses
-x^2-9x+323=0
We add all the numbers together, and all the variables
-1x^2-9x+323=0
a = -1; b = -9; c = +323;
Δ = b2-4ac
Δ = -92-4·(-1)·323
Δ = 1373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{1373}}{2*-1}=\frac{9-\sqrt{1373}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{1373}}{2*-1}=\frac{9+\sqrt{1373}}{-2} $
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